Centroid of trapezium is bit tricky to determine. Because of different lengths a & b with having height “h”.
Centroid of Trapezium Formula:
\(\bar{Y}= \frac{h}{3}\frac{(b+2a)}{(b+a)}\)Example
A trapezium shape is given whose dimensions are;
a = 6’, b = 8’, h = 5’
Find the centroid of trapezium.
Solution
By using formula, centroid of trapezium can be easily determined:
\(\bar{Y}=\frac{5}{3}\frac{(8+2×6)}{(8+6)}\)\(\bar{y}= 2.38’=Answer\)
From where did the y¯ is measured? (from shorter side or longer side?
@ Adi: Take base of trapezoid as reference x-axis
What is the [bar{X}] ?