In this example, readers get clear idea of how to find reactions of simply supported beam when overhang is on both sides of supports.
Example
Calculate of the reactions of simply supported beam with overhang on both sides of support. As shown in figure below.
For calculating reaction R1, take moments about point D
\(\sum M_{D}\space = 0\)Law of equilibrium says;
Clockwise moments = Counter clockwise moments
R1 x 5 + 200 x 2 x 1 = 200 x 2 x 1 + 1000 x 2 + 600 x 7
5R1 + 400 = 400 + 2000 + 4200 = 6600
R1 = 1240 kg
Now for Reaction R2, consider upward forces are equal to downward forces
\(\sum F_{V}\space = 0\)R1 + R2 = 600 + 1000 + 200 x 4
1240 + R2 = 2400
R2 = 2400 -1240
R2 = 1160 kg.
