# Line slope calculator 7x-4y=38

**Straight line given by points A[6; 1] and B[10; 8]**

## Calculation:

**Slope-intercept form of line:**y = 1.75x-9.5

**Canonical form of the line equation:**7x-4y-38 = 0

**Parametric form of the line equation:**

x = 4t+6

y = 7t+1 ; t ∈ R

**Slope:**m = 1.75

**Slope angle of line: φ =**60°15'18″ = 1.0517 rad

**X intercept:**x

_{0}= 5.4286

**Y intercept:**y

_{0}= q = -9.5

**Distance line from the origin:**d

_{0}= 4.7133

**The length of the segment AB: |AB| =**8.0623

**Vector: AB =**(4; 7)

**Normal vector: n =**(7; -4)

**Midpoint of the segment AB: M =**[8; 4.5]

**Perpendicular Bisector equation:**4x+7y-63.5 = 0

**Vector OA = (6; 1) ; |OA| = 6.0828**

**Vector OB = (10; 8) ; |OB| = 12.8062**

**Scalar product OA .OB = 68**

**Angle ∠ AOB = 29°11'51″ = 0.5096 rad**