# Centroid of Trapezium

Centroid of trapezium is bit tricky to determine. Because of different lengths a & b with having height “h”.

## Centroid of Trapezium Formula:

$$\bar{Y}= \frac{h}{3}\frac{(b+2a)}{(b+a)}$$

Example

A trapezium shape is given whose dimensions are;

a = 6’, b = 8’, h = 5’

Find the centroid of trapezium.

### Solution

By using formula, centroid of trapezium can be easily determined:

$$\bar{Y}=\frac{5}{3}\frac{(8+2×6)}{(8+6)}$$

$$\bar{y}= 2.38’=Answer$$

#### 3 Comments

1. Adi September 14, 2013
• Jalal Afsar October 13, 2013
2. Jerald December 8, 2013