In this example, readers get clear idea of how to find reactions of simply supported beam when overhang is on both sides of supports.

##### Example

Calculate of the reactions of simply supported beam with overhang on both sides of support. As shown in figure below.

For calculating reaction R1, take moments about point D

\(\sum M_{D}\space = 0\)Law of equilibrium says;

Clockwise moments = Counter clockwise moments

R1 x 5 + 200 x 2 x 1 = 200 x 2 x 1 + 1000 x 2 + 600 x 7

5R1 + 400 = 400 + 2000 + 4200 = 6600

**R1 = 1240 kg**

Now for Reaction R2, consider upward forces are equal to downward forces

\(\sum F_{V}\space = 0\)R1 + R2 = 600 + 1000 + 200 x 4

1240 + R2 = 2400

R2 = 2400 -1240

**R2 = 1160 kg.**