In this example, one get clear idea how to calculate reactions when a simply supported beam is having overhang on one side of the support.

##### Example

Calculate the reactions of simply supported beam with overhang on left side of support as shown in figure.

##### Solution

Take moment about point C, for reaction R1 \(\sum M_{c}\space = 0\)

Law of equilibrium says;

Clockwise moments = Counter clockwise moments

R1 x 4 = (200 x 4) x 2 + 600 x 6

4R1 = 1600 + 3600 = 5200

**R1 = 1300 kg.**

For reaction R2, consider upward forces are equal to downward forces.

\(\sum F_{V}\space = 0\)R1 + R2 = 600 + 200 x 4

1300 + R2 = 1400

R2 = 1400 – 1300

**R2 = 100 kg.**